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Data Alchemy

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7 contributions to Data Alchemy
Alchemy Codex finished!
I finished part2, The Alchemy Codex. Puh! That's something and a half, or, 'how to put tons of information into pretty short vids'. Respect and admiration for Dave; I think he listed up all the obstacles I most probably would have run into without following his instructions. A lot of questions left, so I need to practice and grind the stuff, like VS Code shortcuts, etc. Anyway, I'm glad I came across this group.
2 likes • Jul 9
Thanks for the note, Rashan.
3 likes • Jun 29
Not reacting but responding... probably just one aspect. The more I think about it, the clearer it becomes to me that I have no idea which pieces of the puzzle suddenly fit together here. I'd better watch ‘Terminator’ again...
Typo in Exercise: Strings and Dictionaries - 3. ?
Hi, I think there is a typo in the python course: Strings and Dictionaries - exercise 3: The proposed solution is not working: def multi_word_search(documents, keywords): keyword_to_indices = {} for keyword in keywords: keyword_to_indices[keyword] = word_search(documents, keyword) return keyword_to_indices 'documents' should be 'doc_list' Unfortunately I don't have the permission to create a new topic on Kaggle....
1 like • Jun 14
@Oriol Fort Yes, it is defined in the exercise No.2: def word_search(doc_list, keyword): # list to hold the indices of matching documents indices = [] # Iterate through the indices (i) and elements (doc) of documents for i, doc in enumerate(doc_list): # Split the string doc into a list of words (according to whitespace) tokens = doc.split() # Make a transformed list where we 'normalize' each word to facilitate matching. # Periods and commas are removed from the end of each word, and it's set to all lowercase. normalized = [token.rstrip('.,').lower() for token in tokens] # Is there a match? If so, update the list of matching indices. if keyword.lower() in normalized: indices.append(i) return indices
Logic problem in Python
Hi, can someone please help me out here. Its Intro to Programming: Conditions and Conditional Statements: Question 1. I tried to solve the problem other than usual, starting with the lowest score. I thought the function would run through all elifs. Now I assume if an elif statement is true it skips the other elifs, otherwise it should set the score to C in the 2nd elif statement. Is that assumption correct? Incorrect: Expected return value of 'C' given score=70, but got 'D' instead. # TODO: Edit the function to return the correct grade for different scores def get_grade(score): if score < 60: grade = "F" elif score >= 60: grade = "D" elif score >= 70: grade = "C" elif score >= 80: grade = "B" elif score >= 90: grade = "A" return grade # Check your answer q1.check() Correct # TODO: Edit the function to return the correct grade for different scores Solution: def get_grade(score): if score >= 90: grade = "A" elif score >= 80: grade = "B" elif score >= 70: grade = "C" elif score >= 60: grade = "D" else: grade = "F" return grade
1 like • Jun 5
@Oriol Fort Thanks. That helps.
1 like • Jun 4
Interesting. Anyway I'm not sure if all plans can be implemented within the scheduled timeframe. And it sometimes it needs the 'killer-application' to introduce a 'disruptive' new technology.
0 likes • Jun 5
@Pierre-Henry Isidor It is. But right now I think there is no killer app for a device without screen, like announced in the vid.
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Jürgen B
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38points to level up
@nick-nice-1087
I'm German, was working as an IT-Security professional and try to get a grip on AI now.

Active 133d ago
Joined May 6, 2025
Germany
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