I got -7 too. When we foil it out, the terms with an x^2 are 16x^2, 9x^2, and pq x^2. Set that equal to 24 and pq becomes -1. Now, the terms with x^3 are just qx^3 and px^3 which must cancel out as they are not present in the final simplified form. It results in p + q being equal to zero. Make p equal to x and q equal to y in the Cartesian plane. It becomes xy = -1 and x + y= 0. You get two solution sets at (-1,1) and (1,-1). Using the first solution set the terms with just an x term becomes 16(-1) + 9(1)= -7. Since p is less than q, this works as p is -1 and q is 1.

6250.

86.

24.

D. 28/q.